MathVista

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When a spring does work on an object, we cannot find the work by simply multiplying the spring force by the object's displacement. The reason is that there is no one value for the force-it changes. However, we can split the displacement up into an infinite number of tiny parts and then approximate the force in each as being constant. Integration sums the work done in all those parts. Here we use the generic result of the integration. In Figure, a cumin canister of mass $m=0.40 \mathrm{~kg}$ slides across a horizontal frictionless counter with speed $v=0.50 \mathrm{~m} / \mathrm{s}$. It then …

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{"category":"math-targeted-vqa","context":"scientific figure","grade":"college","img_height":720,"img_width":1514,"language":"english","skills":["scientific reasoning"],"source":"SciBench","split":"testmini","task":"textbook question answering"}

Hint: Please answer the question requiring a floating-point number with one decimal place and provide the final value, e.g., 1.2, 1.3, 1.4, at the end. Question: When a spring does work on an object, we cannot find the work by simply multiplying the spring force by the object's displacement. The reason is that there is no one value for the force-it changes. However, we can split the displacement up into an infinite number of tiny parts and then approximate the force in each as being constant. Integration sums the work done in all those parts. Here we use the generic result of the integration. …

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what is the total volume of the measuring cup?

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{"category":"general-vqa","context":"natural image","grade":"daily life","img_height":768,"img_width":1024,"language":"english","skills":["numeric commonsense","arithmetic reasoning"],"source":"TextVQA","split":"testmini","task":"visual question answering"}

Hint: Please answer the question requiring an integer answer and provide the final value, e.g., 1, 2, 3, at the end. Question: what is the total volume of the measuring cup? (Unit: g)